Ip addressing lab answers

From Cloonix wiki

1) Please write the base (2) representation of the following base 10 numbers

255 = 11111111

128 = 10000000

64 = 01000000

63 = 00111111

16 = 00010000

15 = 00001111

7 = 00000111

2) Please write the base (8) representation of the same numbers

255 = 377

128 = 200

64 = 100

63 = 77

16 = 20

15 = 17

7 = 7

3) Please convert the following netmasks into binary representation

255.255.255.0 = 11111111.11111111.11111111.00000000

255.255.0.0 = 11111111.11111111.00000000.00000000

255.0.0.0 = 11111111.00000000.00000000.00000000

4) Please write the / notation of the mask

11111111.11111111.00000000.00000000 = /16

11111111.00000000.00000000.00000000 = /8

11111111.11111111.11111111.00000000 = /24

5) Please break the ip addresses given below into network / host sections

123.213.67.9/24

network 123.213.67

host 9

10.34.20.78/8

network 10

host 34.20.78

234.222.111.10/16

network 234.222

host 111.10

6) Given the ip addresses / netmasks give below - are the hosts on the same network

(yes) - they are all on the 10 network - and even tho their masks aren't identical - if configured with the ip and masks shown below - they would be able to communicate (ping back and forth)

10.10.10.10/8

10.10.10.11/8

10.10.10.12/16

7) Extra credit - Do the hosts require a router to communicate?

no